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  4. +2 C and +6 C two charges are repelling each other with a force of 12 N.If a charge of - 2 C is added to each of them, then the value of the force will be

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Q. $+2 \,C$ and $+6 \,C$ two charges are repelling each other with a force of $12 N$.If a charge of $-$ $2 \,C$ is added to each of them, then the value of the force will be

Solution:

Resultant charges after adding the $-2 C$ be $(-2+2)=0$ and $(-2+6)=+4 C$
$ \Rightarrow F =\frac{k\, Q Q_{1} Q_{2}}{r^{2}}=k \times \frac{0 \times 4}{r^{2}}=0$