Question

$2.5F$ of electricity is passed through a $CuS{O}_4$ solution. The number of $gm$ equivalent of $Cu$ deposited on anode is

• A. Zero
• B. $2.5$
• C. $1.25$
• D. $5.0$

Answer 1

Answer: (B)

According to Faradays law, I faraday charge liberated one gram equivalent of a substance during electrolysis.
$\underset{2\times 96500C}{C{u}^{+2}}+2e^{-}⟶\underset{63.5=2\text{equivalents}}{Cu(s)}$
$\therefore EqCu=\frac{2}{2}\times 2.5=2.5Eq$
$\therefore$ Number of equivalents of copper deposited at cathode $=2.5$