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Q.
$2.5 \,F$ of electricity is passed through a $CuSO_{4}$ solution. The number of $gm$ equivalent of $Cu$ deposited on anode is
Electrochemistry
Solution:
According to Faradays law, I faraday charge liberated one gram equivalent of a substance during electrolysis.
$\underset{2 \times 96500\,C}{Cu ^{+2}}+2 e^{-} \longrightarrow \underset{63.5 = 2 \text{equivalents}}{Cu(s)}$
$\therefore Eq Cu=\frac{2}{2} \times 2.5=2.5 Eq$
$\therefore $ Number of equivalents of copper deposited at cathode $=2.5$