Question

$2.5c{m}^3$ of $0.2M{H}_{2}S{O}_4$ solution is diluted to $0.5d{m}^3$ Find normality of the diluted solution:

• A. 0.2 N
• B. 0.02 N
• C. 0.002 N
• D. 0.04 N

Answer 1

Answer: (C)

$V_1=2.5c{m}^3=2.5\times 10^{-3}d{m}^3$

$M_1=0.2M$

$N_1=2\times M_1=0.4N$

$V_2=0.5d{m}^3$

$N_1{V}_1=N_2{V}_2$

$0.4\times 2.5\times 10^{-3}=N_2\times 0.5$

$N_2=2\times 10^{-3}=0.002N$