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Tardigrade
Question
Mathematics
√2+√2+√2+2 cos 8 θ=
Q.
2
+
2
+
2
+
2
cos
8
θ
=
482
170
KCET
KCET 2022
Trigonometric Functions
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A
sin
2
θ
15%
B
2
sin
θ
33%
C
2
cos
θ
33%
D
2
cos
2
θ
18%
Solution:
1
+
cos
θ
=
2
cos
2
(
2
θ
)
2
+
2
+
2
+
2
cos
8
θ
=
2
cos
θ