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  4. √2+√2+√2+2 cos 8 θ=

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Q. $\sqrt{2+\sqrt{2+\sqrt{2+2 \cos 8 \theta}}}=$

KCETKCET 2022Trigonometric Functions

Solution:

$1+\cos \theta=2 \cos ^{2}\left(\frac{\theta}{2}\right)$
$\sqrt{2+\sqrt{2+\sqrt{2+2 \cos 8 \theta}}}=2 \cos \theta$