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Tardigrade
Question
Mathematics
[(169-3/(196)-8)](1/48)=
Q.
\left[\frac{169^{-3}}{(196)^{-8}}\right]^{\frac{1}{48}}=
123
144
Indices
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A
1
3
8
1
1
4
3
1
B
1
3
8
−
1
1
4
3
−
1
C
1
4
3
1
1
3
8
1
D
1
3
3
1
1
4
8
1
Solution:
Simplify the numbers.