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Mathematics
[(169-3/(196)-8)](1/48)=
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Q. $$ \left[\frac{169^{-3}}{(196)^{-8}}\right]^{\frac{1}{48}}= $$
Indices
A
$\frac{14^{\frac{1}{3}}}{13^{\frac{1}{8}}}$
B
$\frac{14^{\frac{-1}{3}}}{13^{\frac{-1}{8}}}$
C
$\frac{13^{\frac{1}{8}}}{14^{\frac{1}{3}}}$
D
$\frac{14^{\frac{1}{8}}}{13^{\frac{1}{3}}}$
Solution:
Simplify the numbers.