13.4 g of a sample of unstable hydrated salt: Na2SO4 ⋅ nH2O was found to contain 6.3 g of water. Determine the number of water of crystallisation.

Question

13.4 g of a sample of unstable hydrated salt: Na2SO4 ⋅ nH2O was found to contain 6.3 g of water. Determine the number of water of crystallisation. (A) 6 (B) 5 (C) 7 (D) 8

Tardigrade Admin · Accepted Answer

( textwt. of water/ textwt. of sample) = ( textwt. of water in the compound/ textmol. wt. of the compound) (6.3/13.4) = (x × 18/142 + 18 x) x = 7

Q. $13.4 g$ of a sample of unstable hydrated salt: $N a_{2} S O_{4} \cdot n H_{2} O$ was found to contain $6.3 g$ of water. Determine the number of water of crystallisation.

$6$

$5$

$7$

$8$

$\frac{wt. of water}{wt. of sample} = \frac{wt. of water in the compound}{mol. wt. of the compound}$
$\frac{6.3}{13.4} = \frac{x \times 18}{142 + 18 x} x = 7$

Q. 13.4g of a sample of unstable hydrated salt: Na2​SO4​⋅nH2​O was found to contain 6.3g of water. Determine the number of water of crystallisation.

6

5

7

8

wt. of samplewt. of water​=mol. wt. of the compoundwt. of water in the compound​ 13.46.3​=142+18xx×18​x=7

Q. $13.4 g$ of a sample of unstable hydrated salt: $N a_{2} S O_{4} \cdot n H_{2} O$ was found to contain $6.3 g$ of water. Determine the number of water of crystallisation.

$6$

$5$

$7$

$8$

$\frac{wt. of water}{wt. of sample} = \frac{wt. of water in the compound}{mol. wt. of the compound}$
$\frac{6.3}{13.4} = \frac{x \times 18}{142 + 18 x} x = 7$