Question

$12g$ carbon combines with $64g$ sulphur to form $C{S}_2$. $12g$ carbon also combines with $32g$ oxygen to form $C{O}_2$. $10g$ sulphur combines with $10g$ oxygen to form $S{O}_2$ These data illustrate the

• A. law of multiple proportions
• B. law of definite proportions
• C. law of reciprocal proportions
• D. law of gaseous volumes

Answer 1

Answer: (C)

Weight of sulphur combining with $12g$ of carbon $=64g$

Weight of oxygen combining with $12g$ of carbon $=32g$

Weight ratio of sulphur and oxygen $=S:O=2:1$

$10g$ of sulphur combines with $10g$ of oxygen to form $S{O}_2$.

$\therefore$ Weight ratio of $S$ and $O$ in $S{O}_2,S:O=1:1$

Hence, it illustrates law of reciprocal proportions.