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  4. 12 g carbon combines with 64 g sulphur to form CS 2. 12 g carbon also combines with 32 g oxygen to form CO 2. 10 g sulphur combines with 10 g oxygen to form SO 2 These data illustrate the

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Q. $12 \,g$ carbon combines with $64 \,g$ sulphur to form $CS _{2}$. $12 \,g$ carbon also combines with $32 \,g$ oxygen to form $CO _{2}$. $10 \,g$ sulphur combines with $10 \,g$ oxygen to form $SO _{2}$ These data illustrate the

Some Basic Concepts of Chemistry

Solution:

Weight of sulphur combining with $12 \,g$ of carbon $=64\, g$

Weight of oxygen combining with $12 \,g$ of carbon $=32\, g$

Weight ratio of sulphur and oxygen $= S : O =2: 1$

$10\, g$ of sulphur combines with $10\, g$ of oxygen to form $SO _{2}$.

$\therefore $ Weight ratio of $S$ and $O$ in $SO _{2}, S : O =1: 1$

Hence, it illustrates law of reciprocal proportions.