10 mL of 1 mM surfactant solution forms a monolayer covering 0.24 cm2 on a polar substrate. If the polar head is approximated as cube, what is its edge length?

Question

10 mL of 1 mM surfactant solution forms a monolayer covering 0.24 cm2 on a polar substrate. If the polar head is approximated as cube, what is its edge length? (A) 2.0 pm (B) 2.0 nm (C) 1.0 pm (D) 0.1 nm

Tardigrade Admin · Accepted Answer

Millimoles = 10 × 10-3 = 10-2 Moles = 10-5 No. of molecules = 6 × 1023 × 10-5 = 6 × 10+18 surface area occupied by one molecule = (0.24/6×1018 ) = 0.04 ×10-18 cm2 4 ×10-20 =a2 a = 2×10-10cm =2pm

Q. 10mL of 1mM surfactant solution forms a monolayer covering 0.24cm2 on a polar substrate. If the polar head is approximated as cube, what is its edge length?

2.0 pm

2.0 nm

1.0 pm

0.1 nm

Millimoles =10×10−3=10−2 Moles = 10−5 No. of molecules = 6×1023×10−5=6×10+18 surface area occupied by one molecule =6×10180.24​=0.04×10−18cm2 4×10−20=a2 a=2×10−10cm=2pm

Q. $10 m L$ of $1 m M$ surfactant solution forms a monolayer covering $0.24 c m^{2}$ on a polar substrate. If the polar head is approximated as cube, what is its edge length?