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  4. 10 mL of 1 mM surfactant solution forms a monolayer covering 0.24 cm2 on a polar substrate. If the polar head is approximated as cube, what is its edge length?

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Q. $10\, mL$ of $1\,mM$ surfactant solution forms a monolayer covering $0.24 \; cm^2$ on a polar substrate. If the polar head is approximated as cube, what is its edge length?

JEE MainJEE Main 2019Surface Chemistry

Solution:

Millimoles $= 10 \times 10^{-3} = 10^{-2} $
Moles = $10^{-5}$
No. of molecules = $6 \times 10^{23} \times 10^{-5} = 6 \times 10^{+18 }$ surface area occupied by one molecule
$= \frac{0.24}{6\times10^{18} } = 0.04 \times10^{-18 } cm^{2} $
$ 4 \times10^{-20} =a^{2}$
$ a = 2\times10^{-10}cm =2pm$