10 mL of 1 N HCl is mixed with 20 mL of 1 M H2SO4 and 30 mL of 1 M NaOH. The resultant solution has:

Question

10 mL of 1 N HCl is mixed with 20 mL of 1 M H2SO4 and 30 mL of 1 M NaOH. The resultant solution has: (A) 20 meq of H+ ions (B) 20 meq of OH- (C) 0 meq of H+ or OH- (D) 30 millimoles of H+

Tardigrade Admin · Accepted Answer

Explanation: No. of meq of H+ = 10 × 1 + 20 × 2 = 50 [∵ H2SO4, N = 2 M] No. of meq of OH- = 30 × 1 = 30 No. of meq of H+ left unreacted = 50 - 30 = 20 meq Hence, (a) is correct, (b), (c) and (d) are ruled out.

Q. $10 m L$ of $1 N H Cl$ is mixed with $20 m L$ of $1 M H_{2} S O_{4}$ and $30 m L$ of $1 M N a O H$ . The resultant solution has:

$20 m e q$ of $H^{+}$ ions

$20 m e q$ of $O H^{-}$

$0 m e q$ of $H^{+}$ or $O H^{-}$

$30$ millimoles of $H^{+}$

Explanation: No. of meq of $H^{+} = 10 \times 1 + 20 \times 2 = 50$
$[∵ H_{2} S O_{4}, N = 2 M]$
No. of meq of $O H^{-} = 30 \times 1 = 30$
No. of meq of $H^{+}$ left unreacted $= 50 - 30 = 20$ meq
Hence, (a) is correct, (b), (c) and (d) are ruled out.

Q. 10mL of 1NHCl is mixed with 20mL of 1MH2​SO4​ and 30mL of 1MNaOH. The resultant solution has:

20meq of H+ ions

20meq of OH−

0meq of H+ or OH−

30 millimoles of H+