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Chemistry
10 mL of 1 N HCl is mixed with 20 mL of 1 M H2SO4 and 30 mL of 1 M NaOH. The resultant solution has:
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Q. $10\, mL$ of $1\, N\, HCl$ is mixed with $20 \,mL$ of $1 \,M \,H_2SO_4$ and $30\, mL$ of $1 \,M \,NaOH$. The resultant solution has:
Some Basic Concepts of Chemistry
A
$20\, meq$ of $H^+$ ions
25%
B
$20\, meq$ of $OH^-$
50%
C
$0\, meq$ of $H^+$ or $OH^-$
25%
D
$30$ millimoles of $H^+$
0%
Solution:
Explanation: No. of meq of $H^+ = 10 \times 1 + 20 \times 2 = 50$
$[\because H_2SO_4, N = 2\,M]$
No. of meq of $OH^- = 30 \times 1 = 30$
No. of meq of $H^+$ left unreacted $= 50 - 30 = 20$ meq
Hence, (a) is correct, (b), (c) and (d) are ruled out.