10 g of hydrogen is reacted with 50 g of oxygen. Calculate the amount of unreacted reagent.

Question

10 g of hydrogen is reacted with 50 g of oxygen. Calculate the amount of unreacted reagent. (A) 6.25 g (B) 3.75 g (C) 3.25 g (D) 2.56 g

Tardigrade Admin · Accepted Answer

underset(4 g)2H2 + underset(32 g)O2 → 2H2O 10 g of hydragen requires (32 × 10 /4) = 80 g of O2 So oxygen is limiting reagent here. ∴ 50 g oxygen reacts with = 4 × 50/32 = 6.25 g of hydrogen Unreacted hydrogen = 10 - 6.25 = 3.75 g

Q. $10 g$ of hydrogen is reacted with $50 g$ of oxygen. Calculate the amount of unreacted reagent.

6.25 g

3.75 g

3.25 g

2.56 g

$(4 g) 2 H_{2} + (32 g) O_{2} \to 2 H_{2} O$
$10 g$ of hydragen requires $\frac{32 \times 10}{4}$
$= 80 g$ of $O_{2}$
So oxygen is limiting reagent here.
$∴ 50 g$ oxygen reacts with $= 4 \times 50/32$
$= 6.25 g$ of hydrogen
Unreacted hydrogen $= 10 - 6.25 = 3.75 g$

Q. 10g of hydrogen is reacted with 50g of oxygen. Calculate the amount of unreacted reagent.