1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is the volume occupied by two moles of gas at 400 mm pressure and at same temperature?

Question

1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is the volume occupied by two moles of gas at 400 mm pressure and at same temperature? (A) 50 mL (B) 100 mL (C) 200 mL (D) 400 mL

Tardigrade Admin · Accepted Answer

Given, p1=100 mm , V1=200 mL p2=400 mm From Boyle's law p1 V1 =p2 V2 V2 =(P1 V1/P2) =(100 × 200/400) V2 = 50 mL Volume of 2 mole gas = 2× 50 = 100 mL

Q. $1$ mole of gas occupies a volume of $200 m L$ at $100 mm$ pressure. What is the volume occupied by two moles of gas at $400 mm$ pressure and at same temperature?

50 mL

100 mL

200 mL

400 mL

Given, $p_{1} = 100 mm, V_{1} = 200 m L$
$p_{2} = 400 mm$
From Boyle's law
$p_{1} V_{1} = p_{2} V_{2}$
$V_{2} = \frac{P _{1} V _{1}}{P _{2}}$
$= \frac{100 \times 200}{400}$
$V_{2} = 50 m L$
Volume of $2$ mole gas $= 2 \times 50$
$= 100 m L$

Q. 1 mole of gas occupies a volume of 200mL at 100mm pressure. What is the volume occupied by two moles of gas at 400mm pressure and at same temperature?