1 mole of FeSO4 (atomic weight of Fe is 55.84 g mol-1) is oxidized to Fe2(SO4)3. Calculate the equivalent weight of ferrous ion

Question

1 mole of FeSO4 (atomic weight of Fe is 55.84 g mol-1) is oxidized to Fe2(SO4)3. Calculate the equivalent weight of ferrous ion (A) 55.84 (B) 27.92 (C) 18.61 (D) 111.68

Tardigrade Admin · Accepted Answer

Atomic mass of Fe =55.84 ∵ Equivalent mass =( text Atomic mass / text Change in oxidation state ) For the charge, Fe 2+ longrightarrow Fe 3+ i.e (3-2=1) the equivalent mass =(55.84/1)=55.84

Q. 1 mole of $F e S O_{4}$ (atomic weight of Fe is $55.84 g m o l^{- 1}$ ) is oxidized to $F e_{2} (S O_{4})_{3}$ . Calculate the equivalent weight of ferrous ion

55.84

27.92

18.61

111.68

83.76

Atomic mass of $F e = 55.84$

$∵$ Equivalent mass $= \frac{Atomic mass}{Change in oxidation state}$

For the charge, $F e^{2 +} ⟶ F e^{3 +}$ i.e $(3 - 2 = 1)$

the equivalent mass $= \frac{55.84}{1} = 55.84$

Q. 1 mole of FeSO4​ (atomic weight of Fe is 55.84gmol−1) is oxidized to Fe2​(SO4​)3​. Calculate the equivalent weight of ferrous ion