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  4. 1 mole of FeSO4 (atomic weight of Fe is 55.84 g mol-1) is oxidized to Fe2(SO4)3. Calculate the equivalent weight of ferrous ion

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Q. 1 mole of $FeSO_4$ (atomic weight of Fe is $55.84 \, g \, mol^{-1}$) is oxidized to $Fe_2(SO_4)_3$. Calculate the equivalent weight of ferrous ion

KEAMKEAM 2018Redox Reactions

Solution:

Atomic mass of $Fe =55.84$

$\because$ Equivalent mass $=\frac{\text { Atomic mass }}{\text { Change in oxidation state }}$

For the charge, $Fe ^{2+} \longrightarrow Fe ^{3+}$ i.e $(3-2=1)$

the equivalent mass $=\frac{55.84}{1}=55.84$