1.12 ml of a gas is produced at STP by the action of 4.12 mg of alcohol, with methyl magnesium iodide. The molecular mass of alcohol is

Question

1.12 ml of a gas is produced at STP by the action of 4.12 mg of alcohol, with methyl magnesium iodide. The molecular mass of alcohol is (A) 16.0 (B) 41.2 (C) 82.4 (D) 156.0

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/b56ccd0d1b39f94e490fa383fe58fd62-.png" /> 1.12 mL is obtained from 4.12 mg ∴ 22400 mL will be obtained from (4.12/1.12) × 22400 mg = 82.4 g

Q. $1.12 m l$ of a gas is produced at $STP$ by the action of $4.12 m g$ of alcohol, with methyl magnesium iodide. The molecular mass of alcohol is

$16.0$

$41.2$

$82.4$

$156.0$

$1.12 m L$ is obtained from $4.12 m g$
$∴ 22400 m L$ will be obtained from
$\frac{4.12}{1.12} \times 22400 m g = 82.4 g$

Q. 1.12ml of a gas is produced at STP by the action of 4.12mg of alcohol, with methyl magnesium iodide. The molecular mass of alcohol is

16.0

41.2

82.4

156.0