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  4. 1.12 ml of a gas is produced at STP by the action of 4.12 mg of alcohol, with methyl magnesium iodide. The molecular mass of alcohol is

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Q. $1.12\, ml$ of a gas is produced at $STP$ by the action of $4.12\, mg$ of alcohol, with methyl magnesium iodide. The molecular mass of alcohol is

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Solution:

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$1.12\, mL$ is obtained from $4.12\, mg$
$\therefore 22400 \, mL$ will be obtained from
$\frac{4.12}{1.12} \times 22400\,mg = 82.4\,g$