1.1 mol of A is mixed with 2.2 mol of B and the mixture is kept in one litre flask till the equilibrium is reached. At equilibrium, 0.2 mol of C is formed. If the equilibrium reaction is A + 2B arrow 2C + D, the value of equilibrium constant is

Question

1.1 mol of A is mixed with 2.2 mol of B and the mixture is kept in one litre flask till the equilibrium is reached. At equilibrium, 0.2 mol of C is formed. If the equilibrium reaction is A + 2B arrow 2C + D, the value of equilibrium constant is (A) 0.0002 (B) 0.0004 (C) 0.001 (D) 0.003

Tardigrade Admin · Accepted Answer

beginmatrixA&+&2B&leftharpoons&2C&+&D endmatrix beginmatrixInitial cone&1.1&2.2&0&0 endmatrix beginmatrixEq. cone&(1.1-0.1)&(2.2-0.2)&0.2&0.1 endmatrix [∵ α=0.1] K=((0.2)2(0.1)/(1.0)(2.0)2)=(0.004/4)=0.001 =1×10-3

Q. 1.1 mol of A is mixed with 2.2 mol of B and the mixture is kept in one litre flask till the equilibrium is reached. At equilibrium, 0.2 mol of C is formed. If the equilibrium reaction is $A + 2 B \to 2 C + D,$ the value of equilibrium constant is

0.0002

0.0004

0.001

0.003

$A + 2 B ⇌ 2 C + D$
$I ni t ia l co n e 1.1 2.2 00$
$Eq . co n e (1.1 - 0.1) (2.2 - 0.2) 0.2 0.1$
$[∵ α = 0.1]$
$K = \frac{( 0.2 ) ^{2} ( 0.1 )}{( 1.0 ) ( 2.0 ) ^{2}} = \frac{0.004}{4} = 0.001$
$= 1 \times 1 0^{- 3}$

Q. 1.1 mol of A is mixed with 2.2 mol of B and the mixture is kept in one litre flask till the equilibrium is reached. At equilibrium, 0.2 mol of C is formed. If the equilibrium reaction is A+2B→2C+D, the value of equilibrium constant is