Question

1.1 mol of A is mixed with 2.2 mol of B and the mixture is kept in one litre flask till the equilibrium is reached. At equilibrium, 0.2 mol of C is formed. If the equilibrium reaction is $A + 2B \rightarrow 2C + D,$ the value of equilibrium constant is

• A. 0.0002
• B. 0.0004
• C. 0.001
• D. 0.003

Answer 1

Answer: (C)

$\begin{matrix}A&+&2B&{\rightleftharpoons}&2C&+&D\end{matrix}$
$\begin{matrix}Initial cone&1.1&2.2&0&0\end{matrix}$
$\begin{matrix}Eq. cone&\left(1.1-0.1\right)&\left(2.2-0.2\right)&0.2&0.1\end{matrix}$
$\left[\because \alpha=0.1\right]$
$K=\frac{\left(0.2\right)^{2}\left(0.1\right)}{\left(1.0\right)\left(2.0\right)^{2}}=\frac{0.004}{4}=0.001$
$=1\times10^{-3}$