0.75 g platinic chloride, a monoacid base on ignition gave 0.245 g platinum. The molecular weight of the base is

Question

0.75 g platinic chloride, a monoacid base on ignition gave 0.245 g platinum. The molecular weight of the base is (A) 75.0 (B) 93.5 (C) 100 (D) 80.0

Tardigrade Admin · Accepted Answer

(Wt. of B2 H2ptCl6/2B+410)=(Wt. of pt/195) ∴ (0.75/2B+410)=(0.245/195) ⇒ B=93.5 Eq. wt. of base = 93.5 ; since it is monoacidic ∴ Mol. wt. of base =93.5×1=93.5

Q. $0.75 g$ platinic chloride, a monoacid base on ignition gave $0.245 g$ platinum. The molecular weight of the base is

$75.0$

$93.5$

$100$

$80.0$

$\frac{W t . o f B _{2} H _{2} ptC l _{6}}{2 B + 410} = \frac{W t . o f pt}{195}$
$∴ \frac{0.75}{2 B + 410} = \frac{0.245}{195}$
$\Rightarrow B = 93.5$
Eq. wt. of base $= 93.5$ ; since it is monoacidic
$∴$ Mol. wt. of base $= 93.5 \times 1 = 93.5$

Q. 0.75g platinic chloride, a monoacid base on ignition gave 0.245g platinum. The molecular weight of the base is

75.0

93.5

100

80.0