Question

0.5 g of metal nitrate gave 0.43 g of metal carbonate. The equivalent weight of metal is _____.

Answer 1

Answer: 166.57

Let the equivalent weight of metal = E

Ew of metal nitrate = Ew of $M+Ew$ of $N{O}_3^{\ominus }=E+62$

Equivalent weight of metal carbonate = Equivalent weight of Metal + Equivalent weight of $C{O}_3^{2-}$

$=E+\frac{60}{2}=E+30$

$\frac{\text{ Ew of metal nitrate }}{\text{ Ew of metal carbonate }}=\frac{\text{ Weight of metal nitrate }}{\text{ Weight of metal carbonate }}$

$\frac{E+62}{E+30}=\frac{0.5}{0.43}$

$\therefore E=166.57$