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  4. 0.5 g of metal nitrate gave 0.43 g of metal carbonate. The equivalent weight of metal is .

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Q. 0.5 g of metal nitrate gave 0.43 g of metal carbonate. The equivalent weight of metal is _____.

Redox Reactions

Solution:

Let the equivalent weight of metal = E

Ew of metal nitrate = Ew of $M + Ew$ of $NO _{3}^{\ominus}= E +62$

Equivalent weight of metal carbonate = Equivalent weight of Metal + Equivalent weight of $CO _{3}^{2-}$

$= E +\frac{60}{2}= E +30$

$\frac{\text { Ew of metal nitrate }}{\text { Ew of metal carbonate }}=\frac{\text { Weight of metal nitrate }}{\text { Weight of metal carbonate }}$

$\frac{E+62}{E+30}=\frac{0.5}{0.43}$

$\therefore E=166.57$