Question

$0.48g$ of a sample of a compound containing boron and oxygen contains $0.192g$ of boron and $0.288g$ of oxygen. What will be the percentage composition of the compound?

• A. $60\%$ and $40\%B$ and $O$ respectively
• B. $40\%$ and $60\%B$ and $O$ respectively
• C. $30\%$ and $70\%B$ and $O$ respectively
• D. $70\%$ and $30\%B$ and $O$ respectively

Answer 1

Answer: (B)

Mass of compound taken $=0.48g$
Mass of boron in sample $=0.192g$
Mass of oxygen in sample $=0.288g$
Percentage of $B=\frac{0.192}{0.48}\times 100=40\%$
Percentage of $O=\frac{0.288}{0.48}\times 100=60\%$