Question

$0.48\, g$ of a sample of a compound containing boron and oxygen contains $0.192\, g$ of boron and $0.288 \,g$ of oxygen. What will be the percentage composition of the compound?

• A. $60\%$ and $40\% B$ and $O$ respectively
• B. $40\%$ and $60\% B$ and $O$ respectively
• C. $30\%$ and $70\% B$ and $O$ respectively
• D. $70\%$ and $30\% B$ and $O$ respectively

Answer 1

Answer: (B)

Mass of compound taken $= 0.48\, g$
Mass of boron in sample $= 0.192\, g$
Mass of oxygen in sample $= 0.288\, g$
Percentage of $ B = \frac{0.192}{0.48} \times 100 = 40\%$
Percentage of $O =\frac{0.288}{0.48} \times 100 = 60\%$