Question

0.45 g of acid (mol. wt. = 90) was exactly neutralized by 20 ml of 0.5 (M) NaOH. The basicity of the given acid is

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (B)

milli equation of acid = milli equation of base
$\frac{0.45}{90}\times basicity=20\times 0.5\times 10^{-3}$
basicity $=\frac{90\times 20\times 0.5\times 10^{-3}}{0.45}$
$=200\times 10^{-3}=2$