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Q. 0.45 g of acid (mol. wt. = 90) was exactly neutralized by 20 ml of 0.5 (M) NaOH. The basicity of the given acid is

Redox Reactions

Solution:

milli equation of acid = milli equation of base
$\frac{0.45}{90} \times basicity =20 \times0.5 \times10^{-3}$
basicity $=\frac{90\times20\times0.5\times10^{-3}}{0.45} $
$=200 \times10^{-3} =2$