Question

0.3 g of an acid is neutralised by 40 $c{m}^3$ of 0.125 N NaOH. Equivalent mass of the acid is

• A. 60
• B. 45
• C. 30
• D. 63

Answer 1

Answer: (A)

For neutralization, no. of gram equivalents of the acid should be equal to no. of gram equivalents of the base.
No. of gram equivalents of NaOH $=\frac{40}{1000}=0.125$
$=5\times 10^{-3}$
Now, $\frac{w}{eq.massofacid}=5\times 10^{-3}$
$\therefore$ Eq.mass of acid = $\frac{0.3}{5\times 10^{-3}}=60$