Question

$0.20g$ of a hydrocarbon on combustion gave $0.66g$ of $C{O}_2$ .The percentage of hydrogen in the hydrocarbon is about

• A. 35
• B. 47
• C. 10
• D. 25

Answer 1

Answer: (C)

$\%$ of $C=\frac{12}{44}\times \frac{\text{ Weight of }C{O}_2}{\text{ Weight of compound }}\times 100$
$=\frac{12}{44}\times \frac{0.66}{0.20}\times 100=90\%$
Thus, $\%$ of $H=100-\%$ of $C$
$=100-90=10\%.$