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  4. 0.20 g of a hydrocarbon on combustion gave 0.66 g of CO2 .The percentage of hydrogen in the hydrocarbon is about

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Q. $0.20\, g$ of a hydrocarbon on combustion gave $0.66\, g$ of $CO_{2}$ .The percentage of hydrogen in the hydrocarbon is about

ManipalManipal 2015

Solution:

$\%$ of $C =\frac{12}{44} \times \frac{\text { Weight of } CO _{2}}{\text { Weight of compound }} \times 100$
$=\frac{12}{44} \times \frac{0.66}{0.20} \times 100=90 \%$
Thus, $\%$ of $H =100-\%$ of $C$
$=100-90=10 \%.$