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Tardigrade
Question
Chemistry
0.126 g of an acid is needed to completely neutralise 20 ml 0.1 (N) NaOH solution. The equivalent weight of the acid is
Q.
0.126
g
of an acid is needed to completely neutralise
20
m
l
0.1
(
N
)
N
a
O
H
solution. The equivalent weight of the acid is
2191
249
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Some Basic Concepts of Chemistry
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A
53
18%
B
40
41%
C
45
21%
D
63
20%
Solution:
∵
Number of milli equivalents of
N
a
O
H
(
n
′
)
=
N
V
=
0.1
×
20
=
2
∴
Number of equivalent
=
0.002
For Neutralisation
Number of equivalent of base
(
N
a
O
H
)
=
Number of equivalent of acid
0.002
=
E
W
=
E
0.126
∴
E
=
0.002
0.126
=
63