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  4. 0.126 g of an acid is needed to completely neutralise 20 ml 0.1 (N) NaOH solution. The equivalent weight of the acid is

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Q. $0.126\, g$ of an acid is needed to completely neutralise $20\,ml$ $0.1\, (N)$ $NaOH$ solution. The equivalent weight of the acid is

WBJEEWBJEE 2017Some Basic Concepts of Chemistry

Solution:

$\because$ Number of milli equivalents of $NaOH$
$\left(n'\right)=N V=0.1 \times 20=2$
$\therefore $ Number of equivalent $=0.002$
For Neutralisation
Number of equivalent of base $( NaOH )$
$=$ Number of equivalent of acid
$0.002 =\frac{W}{E}=\frac{0.126}{E}$
$\therefore E =\frac{0.126}{0.002}=63$