0.102 g of an organic compound X was oxidized with fuming nitric acid. The resulting solution, after reaction with an excess of aqueous BaCl 2, produced 0.233 g of BaSO 4 as a precipitate. Compound X is likely to be: [Given: Atomic wt. of Ba =137]

Question

0.102 g of an organic compound X was oxidized with fuming nitric acid. The resulting solution, after reaction with an excess of aqueous BaCl 2, produced 0.233 g of BaSO 4 as a precipitate. Compound X is likely to be: [Given: Atomic wt. of Ba =137] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

0.233 gm BaSO 4 has 1 millimole BaSO 4 and hence has 1 millimole S ∴ organic compound ( X ) also has 1 millimole S % of S in 0.102 gm of organic compound (X) =(0.032/0.102) × 100=31.37 % <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/65ed2df8453eb568dac50993538d4def-.png" /> 102 gm of this organic compound has 32 gm S This has same % of S

Q. 0.102g of an organic compound X was oxidized with fuming nitric acid. The resulting solution, after reaction with an excess of aqueous BaCl2​, produced 0.233g of BaSO4​ as a precipitate. Compound X is likely to be : [Given: Atomic wt. of Ba=137]

0.233gmBaSO4​ has 1 millimole BaSO4​ and hence has 1 millimole S ∴ organic compound (X) also has 1 millimole S % of S in 0.102gm of organic compound (X) =0.1020.032​×100=31.37% 102gm of this organic compound has 32gmS This has same % of S

Q. $0.102 g$ of an organic compound $X$ was oxidized with fuming nitric acid. The resulting solution, after reaction with an excess of aqueous $B a C l_{2}$ , produced $0.233 g$ of $B a S O_{4}$ as a precipitate. Compound $X$ is likely to be :
[Given: Atomic wt. of $B a = 137]$