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  3. Chemistry
  4. 0.102 g of an organic compound X was oxidized with fuming nitric acid. The resulting solution, after reaction with an excess of aqueous BaCl 2, produced 0.233 g of BaSO 4 as a precipitate. Compound X is likely to be: [Given: Atomic wt. of Ba =137]

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Q. $0.102\, g$ of an organic compound $X$ was oxidized with fuming nitric acid. The resulting solution, after reaction with an excess of aqueous $BaCl _{2}$, produced $0.233 \,g$ of $BaSO _{4}$ as a precipitate. Compound $X$ is likely to be :
[Given: Atomic wt. of $Ba =137]$

KVPYKVPY 2020

Solution:

$0.233\, gm \,BaSO _{4}$ has $1 $ millimole $BaSO _{4}$ and hence has $1$ millimole $S$
$\therefore $ organic compound $( X )$ also has 1 millimole $S$ $\%$ of $S$ in $0.102\, gm$ of organic compound $(X)$
$=\frac{0.032}{0.102} \times 100=31.37 \%$
image
$102\, gm$ of this organic compound has $32 \,gm\, S$
This has same $\%$ of $S$