0.05 F electricity is passed through CuSO 4 solution. Calculate the mass of Cu produced at cathode? (molar mass of C u=63.5 g mol -1 )

Question

0.05 F electricity is passed through CuSO 4 solution. Calculate the mass of Cu produced at cathode? (molar mass of C u=63.5 g mol -1 ) (A) 3.17 g (B) 2.54 g (C) 0.795 g (D) 1.59 g

Tardigrade Admin · Accepted Answer

Equivalent mass of copper =( text Atomic mass / text Valency )=(63.5/2)=31.75 Amount of copper deposited by 0.05 F =0.05 × 3175=1.5875 ∼ e q 1.59 g

Q. $0.05 F$ electricity is passed through $C u S O_{4}$ solution. Calculate the mass of $C u$ produced at cathode? (molar mass of $C u = 63.5 g m o l^{- 1}$ )

$3.17 g$

$2.54 g$

$0.795 g$

$1.59 g$

Equivalent mass of copper
$= \frac{Atomic mass}{Valency} = \frac{63.5}{2} = 31.75$
Amount of copper deposited by $0.05 F$
$= 0.05 \times 3175 = 1.5875 \sim e q 1.59 g$

Q. 0.05F electricity is passed through CuSO4​ solution. Calculate the mass of Cu produced at cathode? (molar mass of Cu=63.5gmol−1 )

3.17g

2.54g

0.795g

1.59g