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Q.
$0.05\,F$ electricity is passed through $CuSO _4$ solution. Calculate the mass of $Cu$ produced at cathode? (molar mass of $C u=63.5\, g\,mol ^{-1}$ )
Equivalent mass of copper
$=\frac{\text { Atomic mass }}{\text { Valency }}=\frac{63.5}{2}=31.75$
Amount of copper deposited by $0.05 F$
$=0.05 \times 3175=1.5875 \sim e q 1.59\, g$