0.005 M acid solution has 5 pH. The percentage ionization of acid is:

Question

0.005 M acid solution has 5 pH. The percentage ionization of acid is: (A)  0.8 %  (B)  0.6 %  (C)  0.4 %  (D)  0.2 %

Tardigrade Admin · Accepted Answer

We know that [ H +]=10- pH =10-5 α=( text actual concentration / text molar concentration ) =(10-5/0.005)=0.2 × 10-2 ∴ percentage ionisation =0.2 × 10-2 × 100 =0.2 %

Q. $0.005 M$ acid solution has $5 p H$ . The percentage ionization of acid is:

$0.8%$

$0.6%$

$0.4%$

$0.2%$

We know that
$[H^{+}] = 1 0^{- p H} = 1 0^{- 5}$
$α = \frac{actual concentration}{molar concentration}$
$= \frac{1 0 ^{- 5}}{0.005} = 0.2 \times 1 0^{- 2}$
$∴$ percentage ionisation
$= 0.2 \times 1 0^{- 2} \times 100$
$= 0.2%$

Q. 0.005M acid solution has 5pH. The percentage ionization of acid is:

0.8%

0.6%

0.4%

0.2%