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  4. 0.005 M acid solution has 5 pH. The percentage ionization of acid is:

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Q. $0.005\,M$ acid solution has $5\,pH$. The percentage ionization of acid is:

Rajasthan PMTRajasthan PMT 2005

Solution:

We know that
$\left[ H ^{+}\right]=10^{- pH }=10^{-5}$
$\alpha=\frac{\text { actual concentration }}{\text { molar concentration }}$
$=\frac{10^{-5}}{0.005}=0.2 \times 10^{-2}$
$\therefore $ percentage ionisation
$=0.2 \times 10^{-2} \times 100$
$=0.2 \%$