0.005 M acid solution has 5 pH. The percentage ionisation of acid is :

Question

0.005 M acid solution has 5 pH. The percentage ionisation of acid is : (A) 0.8% (B) 0.6% (C) 0.4% (D) 0.2%

Tardigrade Admin · Accepted Answer

We know that [H+]=10-pH=10-5 α =( textactual textconcentration/ textmolar textconcentration) =(10-5/0.005)=0.2× 10-2 ∴ percentage ionisation =0.2× 10-2× 100 =0.2%

Q. 0.005 M acid solution has 5 pH. The percentage ionisation of acid is :

0.8%

0.6%

0.4%

0.2%

We know that $[H^{+}] = 10^{- p H} = 10^{- 5}$ $α = \frac{actual concentration}{molar concentration}$ $= \frac{10 ^{- 5}}{0.005} = 0.2 \times 10^{- 2}$ $∴$ percentage ionisation $= 0.2 \times 10^{- 2} \times 100$ $= 0.2$

Q. 0.005 M acid solution has 5 pH. The percentage ionisation of acid is :

0.8%

0.6%

0.4%

0.2%

We know that [H+]=10−pH=10−5 α=molarconcentrationactualconcentration​ =0.00510−5​=0.2×10−2 ∴ percentage ionisation =0.2×10−2×100 =0.2

We know that $[H^{+}] = 10^{- p H} = 10^{- 5}$ $α = \frac{actual concentration}{molar concentration}$ $= \frac{10 ^{- 5}}{0.005} = 0.2 \times 10^{- 2}$ $∴$ percentage ionisation $= 0.2 \times 10^{- 2} \times 100$ $= 0.2$