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  4. 0.005 M acid solution has 5 pH. The percentage ionisation of acid is :

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Q. 0.005 M acid solution has 5 pH. The percentage ionisation of acid is :

WBJEEWBJEE 2006

Solution:

We know that $ [{{H}^{+}}]={{10}^{-pH}}={{10}^{-5}} $ $ \alpha =\frac{\text{actual}\,\text{concentration}}{\text{molar}\,\text{concentration}} $ $ =\frac{{{10}^{-5}}}{0.005}=0.2\times {{10}^{-2}} $ $ \therefore $ percentage ionisation $ =0.2\times {{10}^{-2}}\times 100 $ $ =0.2% $