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Q.
Which one of the following has minimum freezing point ?
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Solution:
Depression in freezing point $\propto$ no. of particles in the solution
$\begin{matrix}&NH_{4}Cl&BaSO_{4}&K_{2}Cr_{2}O_{7}&Al_{2}\left(SO_{4}\right)_{3}\\ {\text{No. of particles}}&2&2&3&5\end{matrix}$
The depression in freezing points $(\Delta T_f)$ will be in the order;
$NH_4Cl = BaSO_4 < K_2Cr_2O_7 < Al_2(SO_4)_3$
Thus, $Al_2(SO_4)_3$ will have maximum depression in freezing point i.e., its actual freezing point will be minimum.