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  4. When the resistance of 9 ohm is connected at the ends of a battery its terminal voltage decreases from 40 volt to 30 volt. The internal resistance of the battery is

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Q. When the resistance of 9 ohm is connected at the ends of a battery its terminal voltage decreases from $40$ volt to $30$ volt. The internal resistance of the battery is

Current Electricity

Solution:

Initially when no current flows, the terminal voltage will be emf so $\varepsilon = 40V$. The internal resistance o f battery is given by
$r=\left(\frac{E}{V}-1\right) R$
$=\left(\frac{40}{30}-1\right) 9$
$=\frac{9 \times 10}{30}=3$ ohm