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Q. Two particles approach each other and their in between distance decreases at the rate of $6$ metre per second. If these particles move in the same direction with different speeds the distance between them increases at the rate of $4$ metre per second, then their speeds are

Motion in a Straight Line

Solution:

If $u_1$ and $u_2$ are the velocities of two particles then in case 1, $u_1 + u_2$ = 6 and in case 2, $u_1 - u_2$ = 4
Adding the two equations, we get, $2u_1$ = 10 i.e. $u_1$ = 5 m $s^{-1}$
Puting, $u_1$ = 5 in any of the above two equations we get $u_2$ = 1 m $s^{-1}$