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Q. Two billiard balls of the same size and mass are in contact on a billiard table. A third ball of the same size and mass strikes them symmetrically and remains at rest after the impact. The coefficient of restitution between the balls is

Work, Energy and Power

Solution:

$m u=2 \,m\, v \cos \theta$
Since all the balls are identical, their centres at the moment of collision form an equilateral triangle. Hence $\theta=30^{\circ}$
$u=2 v \cos 30^{\circ}=\frac{2 v \sqrt{3}}{2}$
$u=v \sqrt{3}$
Using any one ball,
$=\frac{v-0}{u \cos 30^{\circ}-0}$
$=\frac{v}{u \frac{\sqrt{3}}{2}}=\frac{v}{v \sqrt{3} \cdot \frac{\sqrt{3}}{2}}$
$\Rightarrow e=\frac{2}{3}$.
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