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Q. The rule (or effect) which is applied in the following reaction is:
$CH_{3}CHBrCH_{2}CH_{3} \, \overset{ \, \, A l c . K O H \, \, }{ \rightarrow } \, $
(i) $CH_{3}CH=CHCH_{3}$ (major product)
(ii) $CH_{2}=CHCH_{2}CH_{3}$ (minor product)

NTA AbhyasNTA Abhyas 2020

Solution:

Alkyl halides on heating with alcoholic $KOH$ give dehydrogenation reaction to yield alkene. If in reaction, more than one alkenes are formed, then according to Saytzeff, the most highly substituted alkene is the major product.

Solution