Question

The $pH$ of the solution, when
(i) Sodium acetate is dissolved in water
(ii) Ammonium chloride is dissolved in water

• A. $(i)- p H > 7 \,\,(ii)- p H < 7$
• B. $(i)- p H = 7 \,\,(ii)- p H = 0$
• C. $(i)- p H > 7 \,\,(ii)- p H > 7$
• D. $(i)- p H < 7 \,\,(ii)- p H > 7$

Answer 1

Answer: (A)

$\because$ (i) Sodium acetate, i.e. $\left( CH _{3} COONa \right)$ in water gives $CH _{3} COOH$ and $NaOH$ as follows:
$CH _{3} COONa + H _{2} O \rightleftharpoons CH _{3} COOH + NaOH$
Hence, for (i) $p H > 7.\,\,[\because$ solution is basic]
$AlSO$,
(ii) when, ammonium chloride, i.e. $\left( NH _{4} Cl \right)$ is added in water, it gives $NH _{4}^{+}$(aqueous) and $Cl ^{-}$(aqueous) ions.
$NH _{4}^{+}$(aqueous) $+ H _{2} O \rightarrow NH _{3}+ H ^{+}+ OH ^{-}$
Hence, $p H < 7$
i.e. for (i) $p H>7$ and for (ii) $p H<7$.