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Q. The major product obtained when $Br_{2}/Fe$ is treated with Question is

NTA AbhyasNTA Abhyas 2022

Solution:

The benzene ring to which NH group is directly attached is activated for the attack of $Br^{+}$ electrophile, as –NH group is ring activating due to +R effect. The ring to which $C=O$ group is directly attached is deactivated towards electrophilic substitution. As $C=O$ group is ring deactivating due to –R effect in addition the $NH$ group is ortho-para directing but para position is favourable for the attack of $Br^{+}$ . Hence, the product formed is as follows
Solution